3.7. Coflat Disjunctable Analytic Categories
Definition 3.7.1. An analytic category
is coflat
if any map is coflat (or equivalently,
any epi is stable).
Proposition 3.7.2. Suppose A
is a coflat analytic category. Then
(a) Any epi is unipotent.
(b) Any singular mono is analytic.
(c) Any normal mono (thus any
analytic mono) is strong.
(d) If f: Y --> X is a map then f-1:
R(X) --> R(Y) is a morphism of bounded lattices.
(e) R(X) is a distributive lattice for any object X.
(f) If A is locally
disjunctable then any integral object is simple.
Proof. (a) is true because any stable epi is unipotent.
(b) Any singular map in A is coflat, thus
analytic.
(c) The pullback of any normal mono is not proper unipotent, thus not
proper epic by (a).
(d) follows from (1.5.3) because any
map f is coflat.
(e) Suppose w: W --> X, u: U --> X and
v: V --> X are three strong subobjects of X. Then
w (u
v) = w (u
v) = (w u)
(w v) = (w
u) (w
v) by (d).
(f) Since any map is coflat, any non-initial map to an integral object
X is epic by (3.2.6), so X
is simple. 末
In the following we assume A is a coflat
disjunctable analytic category.
Proposition 3.7.3. (a) Any normal mono
is analytic.
(b) Any strong subobject u: U --> X has a negation u
= (u --> 0) in the lattice
R(X).
(c) A strong subobject u: U --> X is analytic iff u
=  u.
Proof. (a) Suppose u: U --> X is a normal mono.
It is strong by (3.7.2.c). Since any strong mono is
disjunctable, the complement uc of u exist, which
is normal, thus also strong. Since u is normal, u is the
complement of uc (i.e. u = (uc)c
), which implies that u is analytic.
(b) and (c) follow from the above proof for (a). 末
Recall that the class of analytic (resp. normal) monos is a subnormal
divisor A (resp. N) on A
(see (2.6.6)). Recall that
is the boolean
functor from A
to the (meta)category of complete boolean algebras, sending each object
X to the set (X)
of normal sieves on object X
(see (2.1.4)).
Proposition 3.7.4. N = A
and is equivalent to
the subnormal framed topology determined by N.
Proof. We already know that N = A by (3.7.3).
To prove the second assertion, consider a normal sieve U on an object
X. Consider any map t: T --> X in U with the
strong image m: e(T) --> X. Since any map is
coflat, by (1.5.2) we have t
= m. Thus  t
=  m.
Since U is a normal sieve, it contains  t,
thus it also contains the normal mono  m.
This indicates that U is generated by the normal mono. Thus U
is a N-sieve for the normal divisor N. Since
any N-sieve is normal, we see that
coincides with the set of N-sieves.
Corollary 3.7.5. The boolean functor
is a framed topology which coincides
with its generic and analytic
topologies. 末
Corollary 3.7.6. Suppose A
is reduced. The following
notions are the same:
(a) Strong mono.
(b) Normal mono.
(c) Analytic mono.
(d) Singular mono.
(e) Fractional mono. 末
In the following we assume X is an object such that R(X)
is complete.
Proposition 3.7.7. Any normal sieve
on X is generated by a normal mono.
Proof. Consider a normal sieve U. Let u: U -->
X be the intersection of all the normal monos v to X
such that the sieve sie(v) generated by v contains
U. Then u is normal. and sie(u) contains U.
We prove that U = sie(u). Suppose t: T --> X
is a map in sie(u) which is disjoint with U. Its strong
image m: S --> X satisfies the similar properties (as u
is a strong mono). Thus m U
which implies that U =  U m
= sie(mc). It follows that u factors through
mc. Since m factors through u, we see that
m factors through mc. Thus m is a initial
map, and t is also initial. This shows that U dominates sie(u).
But U is normal, thus U = sie(u). 末
If D is a divisor on A we
denote by D(X) the set of D-subobjects
of X.
Corollary 3.7.8. (X)
= N(X) = A(X) = A(X).
末
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