Definition 5.4.1. A topological space is quasi-compact if every open cover has a finite subcover. A topological space is noetherian if any subset is quasi-compact in its induced topology. Remark 5.4.2. The following conditions
are equivalent for a topological space:
In a noetherian topological space X, every nonempty closed subset Y can be expressed as a finite union Y = Èi Yi of irreducible closed subsets Yi. The Yi are uniquely determined if Yi Ë Yj for i ¹ j; they are called the irreducible components of Y. A topological space is locally noetherian if any point has a neighborhood which is a noetherian space in its induced topology. Let C be a metric site with finite limits. Definition 5.4.3. A morphism f: X ® Y is called quasi-compact if for any open quasi-compact subset U of |Y|, f-1(U) is quasi-compact (in this case we also say that X is quasi-compact over Y). Definition 5.4.4. A morphism f: X ® Y is called quasi-separated (or X is a Y-object quasi-separated over Y) if the diagonal morphism Df: X ® X ×Y X is universally quasi-compact. We say that X is quasi-separated if X is quasi-separated over the final object Z. Remark 5.4.5. (a) The composite of two
quasi-compact morphisms is quasi-compact.
Proposition 5.4.6. If X is noetherian, then any morphism f: X ® Y is quasi-compact. Proof. Any subset of a noetherian space is quasi-compact, therefore f-1(U) is quasi-compact for any quasi-compact subset U of Y. Proposition 5.4.7. Suppose f: X
® Y is a bicontinuous morphism. Then
f is quasi-compact if any of the following conditions is satisfied:
Proof. Since f is bicontinuous, we can identify |X|
as a subspace of |Y|.
Proposition 5.4.8. Any separated morphism is quasi-separated. In particular, any separated object is quasi-separated. Proof. If f is separated, Df is universally closed, hence universally quasi-compact by (5.4.7.a). Proposition 5.4.9. Suppose f: X
® Y is a morphism. Suppose the underlying
space of Y has a basis B consisting of quasi-compact open subsets.
Then
Proof. (a) Suppose the condition is satisfied. Any quasi-compact
open subset of |Y| is a finite union of the open sets in B.
Therefore for any quasi-compact open subset V of |Y|, f-1(V)
is a finite union of quasi-compact open subsets, hence a quasi-compact
set. The other direction is obvious.
Proposition 5.4.10. Suppose f: X ® Y, g: Y ® Z are two morphisms. If gf is quasi-compact and f is surjective, then g is quasi-compact. Proof. If V is an open quasi-compact subset of Z, f-1(g-1(V)) is quasi-compact, hence f(f-1(g-1(V))) Í |Y| is quasi-compact. But g-1(V) = f(f-1(g-1(V))) as f is surjective. Proposition 5.4.11. (a) The composition
of two quasi-separated morphisms is separated.
Proof. The proofs are similar to those of (5.3.4). Corollary 5.4.12. (a) Suppose X
is quasi-separated. Then any morphism f: X ®
Y is quasi-separated.
Proof. Applying (5.4.11.a and d) to X, Y and the final object Z. Proposition 5.4.13. Suppose f: X ® Y is a morphism, {Ui} is an effective open cover of Y such that each subobject Ui is quasi-separated. Then f is quasi-separated if and only if any subobject Xi = f-1(Ui) is quasi-separated. Proof. For each i denote by fi the restriction
Xi ® Ui.
Then the inverse image of Ui in |X ×Y
X| under the map |X ×Y X|
® |Y| is |Xi ×
Ui Xi|, and the restriction Xi
® Xi ×Ui
Xi of Df
is Dfi. Then by the definition
of quasi-separated morphism and the local nature of quasi-compact morphism,
f is quasi-separated if and only if each fi is
quasi-separated. But by assumption each Ui is
quasi-separated, the proof is finished by (5.4.12.b).
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